MCQ
The transitional metal which form green compound in $ +3 $ oxidation state and yellow orange compound in $+6 $ oxidation state is
- A$Fe$
- B$Ni$
- ✓$Cr$
- D$Co$
✓
Answer
Correct option: C.
$Cr$
c
(c)$(C{r^{ + 6}}{K_2}C{r_2}{O_7} - {\rm{yellow}}$ $C{r^{ + {\rm{3}}}}C{r_2}{(S{O_4})_3}$ -green )
(c)$(C{r^{ + 6}}{K_2}C{r_2}{O_7} - {\rm{yellow}}$ $C{r^{ + {\rm{3}}}}C{r_2}{(S{O_4})_3}$ -green )
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$\begin{array}{*{20}{c}}
{HN = C - linkage\,?} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
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→{HN = C - linkage\,?} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
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