MCQ
The unit of molar conductivity is
- A${\Omega ^{ - 1}}c{m^{ - 2}}mo{l^{ - 1}}$
- B${\Omega ^{}}c{m^{ - 2}}mo{l^{ - 1}}$
- ✓${\Omega ^{ - 1}}c{m^2}mo{l^{ - 1}}$
- D$\Omega \;c{m^2}mol$
So its unit will be ${\Omega ^{ - 1}}c{m^2}mo{l^{ - 1}} $ .
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Given $: \frac{2.303 RT }{ F }=0.06 V$
$Pd _{( aq )}^{2+}+2 e ^{-} \rightleftharpoons Pd ( s ) \quad E ^{\circ}=0.83\,V$
$PdCl _4^{2-}( aq )+2 e ^{-} \rightleftharpoons Pd ( s )+4 Cl ^{-}( aq )$
$E ^{\circ}=0.65\,V$
Compound $(C)$ can show geometrical isomerism. Product $(E)$ of the reaction will be
