MCQ
The units of electrical permittivity are:
- ✓$\ce{N^{-2} m^{-2} C^2}$
- B$\ce{{Nm}^{-2} {C}^2}$
- C$\ce{{C}^2 /{Nm}^2}$
- D$\ce{{n} / {Cm}^2}$
✓
Answer
Correct option: A.
$\ce{N^{-2} m^{-2} C^2}$
$\text{F}=\frac{1}{4\pi\in}\frac{\text{q}_1\text{q}_2}{\text{r}^2}$
$\in\text{ = }\frac{\text{q}_1\text{q}_2}{4\pi\text{Fr}^2}$
$=\frac{\text{C}^2}{\text{Nm}^2}$
$=\text{N}^{-2}\text{m}^{-2}\text{C}^2$
$\in\text{ = }\frac{\text{q}_1\text{q}_2}{4\pi\text{Fr}^2}$
$=\frac{\text{C}^2}{\text{Nm}^2}$
$=\text{N}^{-2}\text{m}^{-2}\text{C}^2$
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