MCQ
The valence shell electronic configuration of $C{r^{2 + }}$ ion is
- ✓$4{s^o}3{d^4}$
- B$4{s^2}3{d^2}$
- C$4{s^2}3{d^0}$
- D$3{p^6}4{s^2}$
$Cr \to [Ar]\,3{d^5}4{s^1}$
$C{r^{2 + }} \to [Ar]3{d^4}4{s^0}$.
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$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.