MCQ
The value of $ \frac{(0.96)^3 - (0.1)^3}{(0.90)^2 + (0.096) + 0.01}$ is
- ✓$0.86$
- B$1.06$
- C$0.95$
- D$0.97$
✓
Answer
Correct option: A.
$0.86$
$ \Rightarrow\frac{(0.96)^3-{(0.1)^3}}{(0.96)^2+(0.096) + 0.01}$
$\Rightarrow\frac{(0.96-0.1)[(0.96)^2+(0.96 \times 0.1 + (0.1)^2]}{(0.96)^2 + (0.096) + (0.01)]} $
$ \Rightarrow\frac{0.86[(0.96)^2 + (0.096 + (0.01)]}{[(0.96)^2 + (0.096) + (0.01)]}$
$ \Rightarrow{ 0.86}$
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