MCQ
The value of $\Big[(81)^{\frac{1}{2}}\Big]^{\frac{1}{2}}$ is:
- A3
- B9
- C-3
- D$\frac{1}{3}$
✓
Answer
- 3
Solution:
$\Big[(81)^{\frac{1}{2}}\Big]^{\frac{1}{2}}$
$=(3^4)^{\frac{1}{2}\times\frac{1}{2}}$
$=(3^4)^{\frac{1}{4}}$
$=3$
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