Question
The value of $\frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09},$ is:

Answer

  1. 2

    Solution:
    $\frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09}$
    $=\frac{(2.3)^3-(0.3)^3}{(2.3)^2+(0.3)^3+(2.3)(0.3)}$
    $=\frac{(2.3 - 0.3)\{(2.3)^2+(0.3)^2+(2.3)(0.3)\}}{((2.3)^2+(0.3)^2+(2.3)(0.3))}$
    $=2.3 - 0.3$
    $=2$
    Hence, correct option is (a).

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