MCQ
The value of $\frac{3\sqrt{12}}{6\sqrt{27}}$ is:
- A$\sqrt{3}$
- B$\frac{1}{3}$
- C$\sqrt{2}$
- D$\frac{1}{2}$
✓
Answer
- $\frac{1}{3}$
Solution:
$\frac{3\sqrt{12}}{6\sqrt{27}}$
$=\frac{3\sqrt{4\times3}}{6\sqrt{9\times3}}\Leftrightarrow\frac{6\sqrt{3}}{18\sqrt{3}}$
$=\frac{1}{3}$
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