MCQ
The value of $\frac{\sqrt{48}+\sqrt{32}}{\sqrt{27}+\sqrt{18}},$ is:
- A$\frac{4}{3}$
- B$4$
- C$3$
- D$\frac{3}{4}$
✓
Answer
- $\frac{4}{3}$
Solution:
$\sqrt{48}=\sqrt{16\times3}=4\sqrt3$
$\sqrt{32}=\sqrt{16\times2}=4\sqrt2$
$\sqrt{27}=\sqrt{9\times3}=3\sqrt3$
$\sqrt{18}=\sqrt{9\times2}=3\sqrt2$
Now, $\frac{\sqrt{48}+\sqrt{32}}{\sqrt{27}+\sqrt{18}}=\frac{4\sqrt3+4\sqrt2}{3\sqrt3+3\sqrt2}$
$=\frac{4\big(\sqrt{\not3}+\sqrt{\not2}\big)}{3\big(\sqrt{\not3}+\sqrt{\not2}\big)}$
$=\frac{4}{3}$
Hence, correct option is (a).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In an isosceles triangle, if the vertex angle is twice the sum of the base angles, then the measure of vertex angle of the triangle is:
- 100º
- 120º
- 110º
- 130º
When p(x) = 4x3 - 12x2 + 11x - 5 is divided by (2x - 1), the remainder is:
The graph of y + 2 = 0 is a line:
- Making an intercept -2 on the x-axis.
- Making an intercept -2 on the y-axis.
- Parallel to the x-axis at a distance of 2 units below the x-axis.
- Parallel to the y-axis at a distance of 2 units to the left of y-axis.
If 10x - 4x2 - 3, then the value of p(0) + p(1) is:
The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8cm and 6cm is:
- A rhombus of area 24cm2
- A rectangle of area 24cm2
- A square of area 26cm2
- A trapezium of area 14cm2
The largest sphere is cut off from a cube of side 6 cm. The volume of the sphere will be
The value of $\frac{(0.013)^3+(0.007)^3}{(0.013)^2-0.013 \times 0.007+(0.007)^2}$, is
→→
A student collects information about the number of schools going children in a locality consisting of a hundred households. The data collected by him is: