MCQ
The value of $\int_3^5 {\frac{{{x^2}}}{{{x^2} - 4}}\,dx} $ is
  • A
    $2 - {\log _e}\left( {\frac{{15}}{7}} \right)$
  • $2 + {\log _e}\left( {\frac{{15}}{7}} \right)$
  • C
    $2 + 4{\log _e}3 - 4{\log _e}7 + 4{\log _e}5$
  • D
    $2 - {\tan ^{ - 1}}\left( {\frac{{15}}{7}} \right)$

Answer

Correct option: B.
$2 + {\log _e}\left( {\frac{{15}}{7}} \right)$
b
(b) $I = \int_3^5 {\left( {1 + \frac{4}{{{x^2} - 4}}} \right)} \,dx.$

Now proceed yourself.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Lines $\frac{1-x}{3}=\frac{y-2}{1}=\frac{z-1}{2}$ and $\frac{x-2}{p}=\frac{y-1}{2}=\frac{z-2}{1}$ are mutually perpendicular to each other then, $p=$ ___________ .
Two cards are drawn from a well shuffled deck of 52 playing cards with replacement. The probability that both cards are queen is
  1. $\frac{1}{13}\times\frac{1}{13}$
  2. $\frac{1}{13}+\frac{1}{13}$
  3. $\frac{1}{13}\times\frac{1}{17}$
  4. $\frac{1}{13}\times\frac{4}{5}$
$\int\limits_0^{\sqrt 3 } {\,\,\frac{1}{2}\,} \,\frac{d}{{dx}}\,\left( {{{\tan }^{ - 1}}\frac{{2x}}{{1 - {x^2}}}} \right)dx$ equals
If $\int \frac{\cos x-\sin x}{\sqrt{8-\sin 2 x}} d x=a \sin ^{-1}\left(\frac{\sin x+\cos x}{b}\right)+c$ where $c$ is a constant of integration, then the ordered pair $( a , b )$ is equal to
Evaluate $\begin{bmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{bmatrix}$ is:
  1. $6-3\sqrt{2}$
  2. $6-\sqrt{2}$
  3. $6+3\sqrt{2}$
  4. $6+\sqrt{2}$
If $f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}
  {\sqrt {1 - x} \,;\,\,\,\,\,\,\,\,\,}&{0 \leqslant x \leqslant 1} \\ 
  {{{\left( {7x - 6} \right)}^{ - 1/3}};}&{1 < x \leqslant 2} 
\end{array}} \right.$ , then $\int\limits_0^2 {f\left( x \right)} dx$ is equal to
If ${I_m} = \int_1^x {{{(\log x)}^m}dx} $ satisfies the relation ${I_m} = k - l{I_{m - 1}},$ then
If $f(x) = \left\{ \begin{array}{l}{(1 + 2x)^{1/x}},\,{\rm{for\,\, }}x \ne 0\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{e^2},\,{\rm{for\,\, }}x = 0\,\,\,\end{array} \right.$, then
For the following probability distribution:

X: -4 -3 -2 -1 0
P(X): 0.1 0.2 0.3 0.2 0.2

The value of E(X) is:

  1. 0
  2. -1
  3. -2
  4. -1.8
Consider the integral

$I=\int_{0}^{10} \frac{[x] e^{[x]}}{e^{x-1}} d x,$

where $[ x ]$ denotes the greatest integer less than or equal to $x$. Then the value of $I$ is equal to: