MCQ
The value of $\left[\left(\frac{1}{4}\right)^{-2}+\left(\frac{1}{3}\right)^{-2}\right] \div\left(\frac{1}{5}\right)^{-2}$ is
- A$0$
- B$-1$
- ✓$1$
- D$\frac{7}{5}$
✓
Answer
Correct option: C.
$1$
$\left(\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{4}\right)^{-2}\right) \div\left(\frac{1}{5}\right)^{-2}$
$\quad=\left[(3)^2+(4)^2\right] \div\left(5^2\right)$
$\quad=(9+16) \div 25$
$\quad=25 \div 25$
$\quad=1$
$\quad=\left[(3)^2+(4)^2\right] \div\left(5^2\right)$
$\quad=(9+16) \div 25$
$\quad=25 \div 25$
$\quad=1$
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