MCQ
The value of $\mathop {\lim }\limits_{a \to 0} \frac{{\sin a - \tan a}}{{{{\sin }^3}a}}$ will be
- ✓$ - \frac{1}{2}$
- B$\frac{1}{2}$
- C$1$
- D$-1$
$= \mathop {\lim }\limits_{a \to 0} \frac{{ - (1 - \cos a)}}{{(1 - {{\cos }^2}a)(\cos a)}}$
$ = \mathop {\lim }\limits_{a \to 0} \left[ { - \frac{1}{{(1 + \cos a)\cos a}}} \right] = - \frac{1}{{(1 + 1)1}} = \frac{{ - 1}}{2}$
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