MCQ
The value of P(n, n - 1) is:
- An
- Bn!
- C2n
- D2n!
Solution:
We know that $\text{P}(\text{n}, \text{r}) = \ ^\text{n}\text{P}_\text{r} = \frac{\text{n}!}{(\text{n}-\text{r})!}$
Hence, $\text{P}(\text{n}, \text{r}) = \ ^\text{n}\text{P}_\text{n-1} = \frac{\text{n}!}{\big[\text{n}-\text{r}\big]!}$
$\text{P}(\text{n, n-1}) = \frac{\text{n!}}{(\text{n}-\text{n}+1)!} = \frac{\text{n}!}{1!} = \text{n}!$
Therefore, the value of $\text{P}(\text{n}, \text{n}-1)$ is $\text{n}!.$
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The distance between the lines y = mx + c1 and y = mx + c2 is: