Question
The value of $\sqrt{3-2\sqrt2},$ is:
✓
Answer
- $\sqrt2-1$
Solution:
$\sqrt{3-2\sqrt2}$
$=\sqrt{2+1-2\sqrt2}$
$=\sqrt{\big(\sqrt2\big)^2+(1)^2-2\big(\sqrt2\big)(1)}$
$=\sqrt{\big(\sqrt2-1\big)^2}$
$=\sqrt2-1$
Hence, correct option is (a).
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