MCQ
The value of $x$ from the given data is
- ✓$0.325$
- B$0.65$
- C$0.25$
- DNone of these
✓
Answer
Correct option: A.
$0.325$
a
$\mathrm{E}_{3}^{\circ}=\frac{\mathrm{n}_{1} \mathrm{E}_{1}^{\circ}+\mathrm{n}_{2} \mathrm{E}_{2}^{\circ}}{\mathrm{n}_{3}} $ $=\frac{1 \times 0.15+1 \times 0.5}{2}$
$\mathrm{E}_{3}^{\circ}=\frac{\mathrm{n}_{1} \mathrm{E}_{1}^{\circ}+\mathrm{n}_{2} \mathrm{E}_{2}^{\circ}}{\mathrm{n}_{3}} $ $=\frac{1 \times 0.15+1 \times 0.5}{2}$
$\mathrm{X} \,volt =0.325 \,\mathrm{volt}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Below are two statements. One is labeled as Assertion $(A)$ and the other as Reason $(R):$
→Assertion $(A):$ $\mathrm{H}_2 \mathrm{Te}$ is more acidic than $\mathrm{H}_2 \mathrm{~S}$.
Reason $(R):$ The bond dissociation enthalpy of $\mathrm{H}_2 \mathrm{Te}$ is less than that of $\mathrm{H}_2 \mathrm{~S}$.
In the context of the above statements, choose the correct answer from the following options:
Ozone with $KI$ solution produces
→A tetrahedral void in a crystal implies that:
Compound $(A)$ will be
→$\mathop {(A)}\limits_{{C_{11}}{H_8}O} \to $ does not under go self aldol condensation
$\mathop {(A)}\limits_{{C_{11}}{H_8}O} \xrightarrow{{{O_3}}}ph\, - \,CHO\, + \,2B\,\xrightarrow{{A{g^ + }}}$ Oxalic acid
The role of conc. ${H_2}S{O_4}$ in the esterification process is
→On hydrolysis, which produces only glucose
The increasing order of magnetism of
→$(I)$ $MnSO_4.4H_2O$ $(II)$ $FeSO_4.7H_2O$
$(III)$ $NiSO_4.6H_2O$ $(IV)$ $CuSO_4.5H_2O$
Ratio of time taken to complete $60\%$ and $20\%$ of first order reaction $[A \rightarrow $ product $]$ is : $(\log\,2 = 0.3)$
→The increasing order of diazotisation of the following compounds is
Which one is most reactive towards ${S_{{N^1}}}$ reaction ?
→