MCQ
The value of 'x' in $3+2^\text{x}=(64)^{\frac{1}{2}}+(27)^{\frac{1}{3}}$ is:
- A3
- B5
- C14
- D8
✓
Answer
- 3
Solution:
$3+2^\text{x}=(64)^{\frac{1}{2}}+(27)^{\frac{1}{3}}$
$\Rightarrow3+2^\text{x}=\sqrt{64}+\sqrt[3]{27}$
$\Rightarrow2^\text{x}=8=2^3$
Equating both,
$\text{x}=3$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In Fig. 17.4, the ratio between the number of students in the year 2016 and 2017 was
The mean of first n natural numbers is:
f (3x - 1)7 = a7x7 + a6x6 + a5x5 + ... + a1x + a0, then a7 + a6 + a5 + ... + a1 + a0 =
In the given figure, O is the centre of a circle in which $\angle\text{OBA}=20^\circ$ and $\angle\text{OCA}=30^\circ.$ Then, $\angle\text{BOC}=?$
→- 50°
- 90°
- 100°
- 130°
In the given figure, O is the centre of a circle and $\angle\text{ACB}=30^\circ.$ Then, $\angle\text{AOB}=?$
→In the following, write the correct answer.
Which of the following is not a criterion for congruence of triangles?
Which of the following is not a criterion for congruence of triangles?
- SAS
- ASA
- SSA
- SSS
Write the correct answer in the following:
AD is a diameter of a circle and AB is a chord. If AD = 34cm, AB = 30cm, the distance of AB from the centre of the circle is:
AD is a diameter of a circle and AB is a chord. If AD = 34cm, AB = 30cm, the distance of AB from the centre of the circle is:
- 17cm.
- 15cm.
- 4cm.
- 8cm.
If $9^{x+2}=240+9^x$,then x =
→The monomial of degree 50 is:
If $x^4+\frac{1}{x^4}=194$, then $x^3+\frac{1}{x^3}=$
→