- A3.5m
- B5.5m
- C7.5m
- D9.5m
Explanation
Using $\text{v}=\text{v}\lambda$ where v is the speed of EM wave.
As $\text{V}=\text{c}=3\times\frac{10\text{m}}{\text{s}}$
$\Rightarrow3\times10^8=40\times10^6\lambda$
$\Rightarrow\lambda=7.5\text{m}$
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Three long, straight and parallel wires carrying currents are arranged as shown in figure. The force experienced by 10 cm length of wire Q is
|
(a) 1.4 |
(b) 1.4 |
|
(c) 2.6 |
(d) 2.6 |
The resultant capacitance between A and B in the following figure is equal to

|
(a) 1 μF |
(b) 3 μF |
(c) 2 μF |
(d) 1.5 μF |
In terms of Rydberg's constant R, the wave number of the first Balmer line is
|
(a) R |
(b) 3R |
(c) |
(d) |