MCQ
The work function of cesium metal is $2eV$. It means that
  • The energy necessary to emit electrons from metal surface is $2eV$
  • B
    The energy of electrons emitted from metallic surface is $2eV$
  • C
    The value of photoelectric current is $2eV$
  • D
    The value of threshold frequency is $2eV$

Answer

Correct option: A.
The energy necessary to emit electrons from metal surface is $2eV$

By definition the work function is the minimum energy $($in electron volts$)$ needed to remove an electron from a solid to a point immediately outside the solid surface $($or energy needed to move an electron from the Fermi level into vacuum$).$
Hence, if the work function of cesium metal is $2ev$, it means that the energy necessary to emit electrons from metal surface is $2eV.$

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