Question
The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?

Answer

$\text{Y}=\frac{\text{stress}}{\text{strain}}$ As per question longitudinal strain for rubber and steel are equal.$\therefore\text{Y}\propto\text{stress}$
$\therefore\frac{\text{Y}_\text{steel}}{\text{Y}_\text{Rubber}}=\frac{\text{(stress})_\text{steel}}{\text{(stress})_\text{Rubber}}\text{ As the Y}_\text{steel}>\text{Y}_\text{Rubber}$
$\therefore\frac{\text{Y}_\text{steel}}{\text{Y}_\text{Rubber}}>1$
$\therefore\text{(stress})_\text{steel}$ is larger than $\text{(stress})_\text{Rubber}$

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