- A${S_2}O_4^{2 - }$
- B${S_2}O_5^{2 - }$
- C${S_2}O_3^{2 - }$
- ✓${S_2}O_7^{2 - }$
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{|\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,|} \\
{{}^ - O - S - O - S - {O^ - }} \\
{|\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,|} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}$
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Statement-$I$ : Noble gases have very high boiling points.
Statement-$II$: Noble gases are monoatomic gases. They are held together by strong dispersion forces. Because of this they are liquefied at very low temperature. Hence, they have very high boiling points. In the light of the above statements. choose the correct answer from the options given below:
Reason : In the presence of a more volatile liquid solute, only the solute will form the vapours and solvent will not.
$n-$propyl bromide $\xrightarrow{{Na}}(A)\xrightarrow[{A{l_2}{O_3}/773\,K}]{{Cr{O_3}}}(B)\xrightarrow[{500\,K}]{{C{l_2}/UV}}(C)$
$n-$propyl bromide $\xrightarrow{{Na}}(A)\xrightarrow[{A{l_2}{O_3}/773\,K}]{{Cr{O_3}}}(B)$ $\xrightarrow[{}]{{C{H_3} - Cl/AlC{L_3}}}(D)\xrightarrow{{C{l_2}/hv}}(E)$
