MCQ
Thiosulphate reacts differently with iodine and bromine in the reactions given below: $\ce{2 {S}_2{O}^{2-}_3 + {I}\xrightarrow{ \ \ \ \ \ \ \ } {S}_4{O}^{2-}_6 + 2 {I}^{-}{S}_2{O}^{2-}_3 + 2{Br}_2 + 5 {H}_2{O}\xrightarrow{ \ \ \ \ \ \ \ }2{SO}^{2-}_4 + 2 {Br}^{-} + 10 {H}^{+}}$ Which of the following statements justifies the above dual behaviour of thiosulphate?
  • Bromine is a stronger oxidant than iodine.
  • B
    Bromine is a weaker oxidant than iodine.
  • C
    Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions.
  • D
    Bromine undergoes oxidation and iodine undergoes reduction in these reactions.

Answer

Correct option: A.
Bromine is a stronger oxidant than iodine.
$\ce{2{S}_2{O}^{2-}_3({aq}) + {I}_2 {(s)}\xrightarrow{ \ \ \ \ \ \ \ \ \ } {S}_4{O}^{2-}_6({aq}) + 2{I}^{-}({aq})$
${S}_2{O}^{2-}_3({aq}) + 2{Br}({l}) + 5{H}_2 {O}({l})\xrightarrow{ \ \ \ \ \ \ \ \ \ }2{SO}^{2-}_4({Aq}) + 4 {Br}^{-}({aq}) + 10 {H}^{+}({aq})}$
Bromine being stronger oxidizing agent than $I_2$, it oxidises S of $\mathrm{S}_2  \mathrm{O}^{2-}{ }_3$ to $\mathrm{SO}^{2-}{ }_4$ whereas $\mathrm{I}_2$ oxidises it only into $\mathrm{S}_4 \mathrm{O}^{2-}{ }_6$ ion.
 

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