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Capacitors — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsCapacitors1 Mark
MCQ
Three capacitors of capacitances $6\mu\text{F}$ each are available. The minimum and maximum capacitances, which may be obtained are:
  • A
    $6\mu\text{F},\ 18\mu\text{F}$
  • B
    $3\mu\text{F},\ 12\mu\text{F}$
  • C
    $2\mu\text{F},\ 12\mu\text{F}$
  • ✓
    $2\mu\text{F},\ 18\mu\text{F}$
✓

Answer

Correct option: D.
$2\mu\text{F},\ 18\mu\text{F}$
Explanation:
The minimum capacitance can be obtained by connecting all capacitors in series. It can be calculated as follows:
$\frac{1}{\text{C}}=\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{1}{2}$
$\Rightarrow\text{C}=2\mu\text{F}$
The maximum capacitance can be obtained by connecting all capacitors in parallel. It can be calculated as follows:
$\text{C}=6+6+6=18\mu\text{F}$

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