MCQ
Three coins are tossed si multaneously. What is the probability of getting exactly two heads?
- A$\frac{1}{2}$
- B$\frac{1}{4}$
- ✓$\frac{3}{8}$
- D$\frac{3}{4}$
✓
Answer
Correct option: C.
$\frac{3}{8}$
(c)
When 3 coins are tossed, all possible outcomes are HHH, HHT, HTH, THH, HTT, THT, TTH, TTT
= 8 numbers
Fovourable outcomes = HHT, HTH, THH $=3$ numbers
$\therefore$ Required probability $=\frac{3}{8}$
When 3 coins are tossed, all possible outcomes are HHH, HHT, HTH, THH, HTT, THT, TTH, TTT
= 8 numbers
Fovourable outcomes = HHT, HTH, THH $=3$ numbers
$\therefore$ Required probability $=\frac{3}{8}$
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