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STD 11 - 3.1 , vectors — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 3.1 , vectors4 Marks
MCQ
Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces  Also name the triangle formed by the forces as sides
  • ✓
    $120^°$ equilateral triangle
  • B
    $60^°$ equilateral triangle
  • C
    $120^°, 30^°, 30^° $ an isosceles triangle
  • D
    $120^°$ an obtuse angled triangle
✓

Answer

Correct option: A.
$120^°$ equilateral triangle
a
(a) In $N$ forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$\theta = \frac{{360}}{N}$$ = \frac{{360}}{3} = 120^\circ $

If these three vectors are represented by three sides of triangle then they form equilateral triangle

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