Question
Three circuits, each consisting of a switch $'S\ ’$ and two capacitors, are initially charged, as shown in the figure. After the switch has been closed, in which circuit will the charge on the left$-$hand capacitor $(i)$ increase, $(ii)$ decrease and $(iii)$ remain same? Give reasons.

Answer

$V_L = 3?$ $V_R = 3?$ $(L:$ Left, $R:$ Right$)$
$V_L = 6?$ $V_R = 3?$  
$V_L = 2?$ $V_R= 3?$  
Reasons:
  1. No change $– ($ potential same on both capacitors as $(V_L = V_R).$
  2. Charge on left hand capacitor will decrease$ (V_L > V_R).$
  3. Charge on left hand capacitor will increase $(V_R > V_L).$

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