MCQ
Three equal capacitors, each with capacitance $C$ are connected as shown in figure. Then the equivalent capacitance between $A$ and $B$ is


- A$C$
- ✓$3C$
- C$\frac{C}{3}$
- D$\frac{{3C}}{2}$


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| Object Pin | Convex Lens | Convex Mirror | Image Pin |
| $22.2\,cm$ | $32.2\,cm$ | $45.8\,cm$ | $71.2\,cm$ |
The focal length of the convex lens is $f_1$ and that of mirror is $f_2$. Then taking index correction to be negligibly small, $f_1$ and $f_2$ are close to