MCQ
Three identical vessels $A, B$ and $C$ contain same quantity of liquid. In each vessel, blocks with different densities but same masses are placed as shown in figure. If $F_A, F_B$ and $F_C$​​​​​​​ are the total forces acting on the base of vessels $A, B$ and $C$ respectively, then:
​​​​​​​
  • $FA = FB = FC$
  • B
    $FA < FB < FC$
  • C
    $FA = FB < FC$
  • D
    $FA > FB > FC$

Answer

Correct option: A.
$FA = FB = FC$
Force acting on the base of vessels $A, B$ and $C$ is the weight of block and weight of water, which is same for all the three vessels. Hence, $F_{A }= F_{B }= F_C.$

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