- ✓$\frac{{{r_1}{r_2}}}{{r_3^2}} = $ constant
- B${r_1}{r_2}{r_3}^2 = $ constant
- C${r_1}{r_2}{r_3}^{1/2} = $ constant
- D${r_1}{r_2}{r_3} = $ constant
$=\frac{\mathrm{r}_{3}^{2}}{\mathrm{r}_{1} \mathrm{r}_{2}}=$ const.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


Statement $I$ : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit $\left( E _{1}\right)$ to higher energy orbit $\left( E _{2}\right)$, is given as $hf = E _{1}- E _{2}$.
Statement $II$ : The jumping of electron from higher energy orbit $\left(E_{2}\right)$ to lower energy orbit $\left(E_{1}\right)$ is associated with frequency of radiation given as $f$ $=\left( E _{2}- E _{1}\right) / h$
This condition is Bohr's frequency condition. In the light of the above statements, choose the correct answer from the options given below