MCQ
Three plates of common surface area $A$ are connected as shown. The effective capacitance will be
- A$\frac{{{\varepsilon _0}A}}{d}$
- B$\frac{{3{\varepsilon _0}A}}{d}$
- C$\frac{3}{2}\frac{{{\varepsilon _0}A}}{d}$
- ✓$\frac{{2{\varepsilon _0}A}}{d}$
