MCQ
Three unbiased coins are tossed simultaneously. The probability of getting at most two heads is:
  • A
    $\frac{1}{2}$
  • B
    $\frac{3}{8}$
  • C
    $\frac{5}{8}$
  • $\frac{7}{8}$

Answer

Correct option: D.
$\frac{7}{8}$
(d) $\frac{7}{8}$
Explanation:
Given, n(S)={ HHH , HHT , HTH , HTT ,TTT, TTH, THT, THH}
$n(S)=8$
and n(E )= { HHT , HTH , HTT , THH ,THT, TTH, TTT }
$n( E )=7$
$\therefore P ( E )=\frac{n(F)}{n(S)}=\frac{7}{8}$.

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