Question
To reduce the ripples in a rectifier circuit with capacitor filter:

Answer

$R_L$ should be increased.
Input frequency should be increased.
​​​​​Capacitors with high capacitance should be used.
Ripple factor may be defined as the ratio of $\text{r.m.s}$. value of the ripple voltage to the absolute value of the $DC$ component of the output voltage, usually expressed as a percentage.
However ripple voltage is also commonly expressed as the peak $-$ to $-$ peak value.
Ripple factor $(r)$ of a full wave rectifier using capacitor filter is given by
$\text{r}=\frac{0.236\text{R}}{\omega\text{L}}$
where $,L$ is inductance of the coil and $\omega$ is the angular frequency.
or Ripple factor can also be given by
$\text{r}=\frac{1}{4\sqrt{3}\text{v}\text{R}_\text{L}\text{C}_\text{V}}$
i.e., $\text{r}\propto\frac{1}{\text{R}_\text{L}}\Rightarrow\ \text{r}\propto\frac{1}{\text{C}},\text{r}\propto\frac{1}{\text{V}}$
Ripple factor is inversely proportional to $R_L, C$ and $v$.
Thus to reduce $r, R_L$ should be increased, input frequency $v$ should be increased and capacitance $C$ should be increased.

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