MCQ
Total number of $d$ electrons present an element with atomic no. $78$ is
  • A
    $8$
  • B
    $58$
  • C
    $28$
  • $29$

Answer

Correct option: D.
$29$
d
${}_{78}Pt = 3{d^{10}} + 4{d^{10}} + 5{d^9} = 29\,{e^{ - 1}}s$

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