MCQ
Total number of electrons in $“Cu”$ atom having $m_l = 0$
- A$9$
- ✓$13$
- C$10$
- D$6$
$\therefore m_l = 0$ will be $= 2 + 2 + 2 + 2 + 2 + 1 + 2 = 13$
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$C{H_3}C{H_2}I + KO{H_{(aq)}} \to C{H_3}C{H_2}OH + KI$
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