- ACr
- BCo
- CCu
- DNi
Explanation:
Cr and Co form MF3 type of compounds. The ability of fluorine to stabilize the highest oxidation state is due to higher lattice energy in CoF3 and higher bond enthalpy for the higher covalent compound like CrF6.
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$(i)$ Hinsberg test
$(ii)$ Carbyl amine test
$(iii)$ Hofmann mustard oil test
$(iv)$ $HNO_2$ test
$\begin{align}
\begin{matrix}
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,O \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,|| \\
H-O-C-C- \\
\end{matrix}\begin{matrix}
O\,\, \\
||\,\,\, \\
C{{H}_{2}}-C-O-H \\
\end{matrix} \\
p{{K}_{a}}=2.2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,p{{K}_{a}}=3.98 \\
\end{align}$
Reason : Fluorine has $2s^2\,2p^5$ configuration.