- AHigh ionization potential and low melting point.
- BHigh ionization potential and high melting point.
- CLow ionization potential and low melting point.
- DLow ionization potential and high melting point.
Explanation:
Transition metals are less reactive relative to I and II group due to higher ionization potential and high melting point (due to greater no of bonding electrons).
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Product $(A)$ of the reaction is
[${\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{O}} =$ mass $- 18$ isotope of oxygen]
$A, C$ and $D$ are :-
| gas | $Ar$ | $Ne$ | $Kr$ | $Xe$ |
| $a /\left( atm \,dm ^{6} \,mol ^{-2}\right)$ | $1.3$ | $0.2$ | $5.1$ | $4.1$ |
| $b /\left(10^{-2} \,dm ^{3}\, mol ^{-1}\right)$ | $3.2$ | $1.7$ | $1.0$ | $5.0$ |
Which gas is expected to have the highest critical temperature?
Assertion $A:$ A mixture contains benzoic acid and napthalene. The pure benzoic acid can be separated out by the use of benzene.
Reason $R:$ Benzoic acid is soluble in hot water.
In the light of the above statements, choose the most appropriate answer from the options given below.