MCQ
$\triangle A B C$ is such that $A B=3 cm, B C=2 cm, C A=2.5 cm$. If $\triangle A B C \sim \triangle D E F$ and $E F=4 cm$, then perimeter of $\triangle D E F$ is
- A7.5 cm
- ✓15 cm
- C22.5 cm
- D30 cm
✓
Answer
Correct option: B.
15 cm
(B)15 cm
Given that $\triangle A B C \sim \triangle D E F$.
$
\therefore \quad \frac{A B}{D E}=\frac{B C}{E F}=\frac{A C}{D F}=\frac{A B+B C+C A}{D E+E F+D F} \Rightarrow \frac{2}{4}=\frac{3+2+2.5}{\text { Perimeter of } \triangle D E F} \Rightarrow \text { Perimeter of } \triangle D E F=15 cm
$
Given that $\triangle A B C \sim \triangle D E F$.
$
\therefore \quad \frac{A B}{D E}=\frac{B C}{E F}=\frac{A C}{D F}=\frac{A B+B C+C A}{D E+E F+D F} \Rightarrow \frac{2}{4}=\frac{3+2+2.5}{\text { Perimeter of } \triangle D E F} \Rightarrow \text { Perimeter of } \triangle D E F=15 cm
$
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