MCQ
True order of bond angle is
- ✓${H_2}O > {H_2}S > {H_2}Se > {H_2}Te$
- B${H_2}Te > {H_2}Se > {H_2}S > {H_2}O$
- C${H_2}S > {H_2}O > {H_2}Se > {H_2}Te$
- D${H_2}O > {H_2}S > {H_2}Te > {H_2}Se$
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$N{H_4}^ + + {S^{ - 2}} \rightleftharpoons N{H_3} + H{S^ - }$
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ are $(n +1)$
$(b)$ When $F_2$ reacts with $H_2O$ it forms $HF,$ $O_2$ & $O_3.$
$(c)$ $XeF_6$ on hydrolysis shows disproportionation reaction
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al (OH)_3$ as a final product
$A: \left[ Ni ( en )_{3}\right]^{2+}, B :\left[ Ni \left( NH _{3}\right)_{6}\right]^{2+}, C :\left[ Ni \left( H _{2} O \right)_{6}\right]^{2+}$