MCQ
True order of bond angle is
- ✓${H_2}O > {H_2}S > {H_2}Se > {H_2}Te$
- B${H_2}Te > {H_2}Se > {H_2}S > {H_2}O$
- C${H_2}S > {H_2}O > {H_2}Se > {H_2}Te$
- D${H_2}O > {H_2}S > {H_2}Te > {H_2}Se$
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$Fe|FeSO_4$ $E^o_{OP} = 0.44\, V$ $(a = 0.1\, M)$
$(a)$ saline hydrides produce $H_2$ gas when reacted with $H_2O.$
$(b)$ reaction of $LiAH_4$ with $BF_3$ leads to $B_2H_6.$
$(c)$ $PH_3$ and $CH_4$ are electron - rich and electron-precise hydrides, respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.
$(i)$ $PtCl _{4} . 5 NH _{3}$ $(ii)$ $PtCl _{4} . 4 NH _{3}$ $(iii)$ $PtCl _{4} . 3 NH _{3}$ $(iv)$ $PtCl _{4}. 2 NH _{3}$
Follow the order