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2. motion in straight line — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics2. motion in straight line1 Mark
MCQ
Two bodies are thrown simultaneously from a tower with same initial velocity ${v_0}:$ one vertically upwards, the other vertically downwards. The distance between the two bodies after time $t$ is
  • A
    $2{v_0}t + \frac{1}{2}g\,{t^2}$
  • ✓
    $2{v_0}t$
  • C
    ${v_0}t + \frac{1}{2}g\,{t^2}$
  • D
    ${v_0}t$
✓

Answer

Correct option: B.
$2{v_0}t$
b
(b) For vertically upward motion, ${h_1} = {v_0}t - \frac{1}{2}g\,{t^2}$and for vertically down ward motion, ${h_2} = {v_0}t + \frac{1}{2}g\;{t^2}$

$\therefore $ Total distance covered in $t \,sec$ $h = {h_1} + {h_2} = 2{v_o}t$.

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