MCQ
Two capacitors, each having capacitance $40\,\mu F$ are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant $K$ such that the equivalence capacitance of the system became $24\,\mu F$. The value of $K$ will be.
  • $1.5$
  • B
    $2.5$
  • C
    $1.2$
  • D
    $3$

Answer

Correct option: A.
$1.5$
a
$C _{ eq }=\frac{ C ( KC )}{ C + KC }=\frac{ KC }{ K +1}$

$24=\frac{K 40}{K+1}$

${[K=1 \cdot 5] }$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free