MCQ
Two coins are tossed together. The probability of getting at most one head is :
- A$1$
- B$\frac{1}{4}$
- ✓$\frac{3}{4}$
- D$\frac{2}{4}$
✓
Answer
Correct option: C.
$\frac{3}{4}$
Number of Total outcomes $= \text{\{HH, HT, TH, TT}\} = 4$
Number of possible outcomes $= \text{\{(HH, HT, TH)}\} = 3$
$\therefore$ Required Probability $=\frac{3}{4}$
Number of possible outcomes $= \text{\{(HH, HT, TH)}\} = 3$
$\therefore$ Required Probability $=\frac{3}{4}$
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