Question
Two dice are thrown at the same time. Determine the probabiity that the difference of the numbers on the two dice is 2.
✓
Answer
The total number of sample space in two dice, n(S) = 6 × 6 = 36
Let E = Event of getting the number whose difference is 2.
= {(1, 3), (2, 4), (3, 5), (4, 6), (3, 1), (4, 2), (5, 3), (6, 4)}
$\therefore$ n(E) = 8
$\therefore\ \ \text{P(E})=\frac{\text{n(E})}{\text{n(S)}}=\frac{8}{36}=\frac{2}{9}$
Let E = Event of getting the number whose difference is 2.
= {(1, 3), (2, 4), (3, 5), (4, 6), (3, 1), (4, 2), (5, 3), (6, 4)}
$\therefore$ n(E) = 8
$\therefore\ \ \text{P(E})=\frac{\text{n(E})}{\text{n(S)}}=\frac{8}{36}=\frac{2}{9}$
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