Question
Two electric bulbs whose resistances are in the ratio 1 : 2 are connected in parallel to a source of constant voltage. What will be the ratio of power dissipation in these wires?

Answer

Power $\text{P}=\frac{\text{V}^2}{\text{R}}\propto\frac{1}{\text{R}}$ For same valtage, the bulbs being in parallel.
$\frac{\text{P}_1}{\text{P}_2}=\frac{\text{R}_2}{\text{R}_1}=\frac{2}{1}.$
Thus, ratio of power dissipated is 2 : 1.

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