MCQ
Two intersecting lines cannot be parallel to the same line is stated in the form of:
- AA theorem.
- BA postulate.
- CA definition.
- DNone of these.
✓
Answer
- A postulate.
Solution:
Euclid's fifth postulate can also be stated in the following form: Two distinct intersecting lines cannot be parallel to the same line.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The smallest rational number by which $\frac{1}{3}$ should be multiplied so that its decimal expansion terminates after one place of decimal, is:
→If the sum of all the edges of a cube is a 36cm, them the volume (in cm3) of that cube is:
In Fig. PQ ||RS, $\angle A E F=95^{\circ}, \angle B H S=110^{\circ}$ and $\angle A B C=x^{\circ}$.Then the value of x is
→If the line represented by the equation 3x + ky = 9 passes through the points (2, 3), then the value of k is:
If $f(x+3)=x^2-7 x+2$, then the remainder when $f(x)$ is divided by $(x+1)$, is
→The figure formed by joining the midpoints of the adjacent sides of a rectangle of sides 8cm and 6cm is a:
- Rectangle of area 24cm2
- Square of area 24cm2
- Trapezium of area 24cm2
- Rhombus of area 24cm2
The rationalisation factor of $\frac{1}{\big(2\sqrt{3}-\sqrt{5}\big)}$ is:
→- $\sqrt{5}-2\sqrt{3}$
- $\sqrt{3}+2\sqrt{5}$
- $\big(\sqrt{3}+\sqrt{5}\big)$
- $\sqrt{12}+\sqrt{5}$
In the given figure, AB || CD. If $\angle\text{EAB}=50^\circ$ and $\angle\text{ECD}=60^\circ$ then $\angle\text{AEB}=?$
→- 50º
- 60º
- 70º
- 55º
D and E are the mid-points of the sides AB and AC res. Of $\triangle\text{ABC}.$ DE is produced to F. To prove that CF is equal and parallel to DA, we need an additional information which is:
→