- AA loss of kinetic energy
- BThe destruction of the waves
- CThe reversal of the direction of the waves
- ✓A larger wave
For constructive interference,
$A_R=A_1+A_2$
Due to the constructive interference of the superimposing waves, resultant wave of larger amplitude is obtained and hence constructive interference results in the larger wave.
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Statement $I$ : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit $\left( E _{1}\right)$ to higher energy orbit $\left( E _{2}\right)$, is given as $hf = E _{1}- E _{2}$.
Statement $II$ : The jumping of electron from higher energy orbit $\left(E_{2}\right)$ to lower energy orbit $\left(E_{1}\right)$ is associated with frequency of radiation given as $f$ $=\left( E _{2}- E _{1}\right) / h$
This condition is Bohr's frequency condition. In the light of the above statements, choose the correct answer from the options given below



