MCQ
Two long current carrying thin wires, both with current $I$, are held by insulating threads oflength $L$ and are in equilibrium as shown in the figure, with threads making an angle '$\theta$' with the vertical. If wires have mass $\lambda$ per unit length then the value of $l$ is
($g =$ gravitational acceleration)
($g =$ gravitational acceleration)
- ✓$2$$sin$$\theta \sqrt {\frac{{\pi \lambda gL}}{{{\mu _0}cos\theta }}} \;\;\;\;\;\;\;\;$
- B$2$$\sqrt {\frac{{\pi gL}}{{{\mu _0}}}tan\theta } $
- C$\;\sqrt {\frac{{\pi \lambda gL}}{{{\mu _0}}}tan\theta } $
- D$sin$$\theta \sqrt {\frac{{\pi \lambda gL}}{{{\mu _0}cos\theta }}} $
