MCQ
Two metallic charged spheres whose radii are $20\,cm$ and $10\,cm$ respectively, have each $150\,micro - coulomb$ positive charge. The common potential after they are connected by a conducting wire is
  • $9 \times {10^6}\;volts$
  • B
    $4.5 \times {10^6}\;volts$
  • C
    $1.8 \times {10^7}\;volts$
  • D
    $13.5 \times {10^6}\;volts$

Answer

Correct option: A.
$9 \times {10^6}\;volts$
a
(a) Common potential $V = \frac{{{\rm{Total \,charge }}}}{{{\rm{Total \,capacitance}}}}$
$V = \frac{{150 \times {{10}^{ - 6}} \times 2}}{{4\pi {\varepsilon _0}(10 \times {{10}^{ - 2}} + 20 \times {{10}^{ - 2}})}} = 9 \times {10^6}\,V$

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