Download App
Two oscillating systems; a simple pendulum and a vertical spring-mass-system have same time period of motion on the surface of the Earth. If both are taken to the moon, then-
  • A
    Time period of the simple pendulum will be more than that of the spring-mass system.
  • B
    Time period of the simple pendulum will be equal is that is of the spring-mass system.
  • C
    Time period of the simple pendulum will be less than of the spring-mass system.
  • D
    Nothing can be said definitely without observation.
Medium
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Download App

Similar Questions

  • 1
    A mass m performs oscillations of period $T$ when hanged by spring of force constant $K$. If spring is cut in two parts and arranged in parallel and same mass is oscillated by them, then the new time period will be
    View Solution
  • 2
    A pendulum is suspended by a string of length $250\,cm$. The mass of the bob of the pendulum is $200\,g$. The bob is pulled aside until the string is at $60^{\circ}$ with vertical as shown in the figure. After releasing the bob. the maximum velocity attained by the bob will be________ $ms ^{-1}$. (if $g=10\,m / s ^{2}$ )
    View Solution
  • 3
    The displacement of simple harmonic oscillator after $3$ seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is $\dots \; s$
    View Solution
  • 4
    If pendulum is released from given position find velocity of Bob when it reaches the lowest position
    View Solution
  • 5
    The piston in the cylinder head of locomotive has a stroke of $6\,m$ (which is twice the amplitude). If the piston executing simple harmonic motion with an angular frequency of $200\, rad\, min^{-1}$, its maximum speed is .... $ms^{-1}$
    View Solution
  • 6
    A particle starts from a point $P$ at a distance of $A/2$ from the mean position $O\, \&$ travels towards left as shown in the figure. If the time period of $SHM,$ executed about $O$ is $T$ and amplitude $A$ then the equation of motion of particle is :
    View Solution
  • 7
    A particle of mass m is executing oscillations about the origin on the $X-$axis. Its potential energy is $U(x) = k{[x]^3}$, where $k$ is a positive constant. If the amplitude of oscillation is $a$, then its time period $T$ is
    View Solution
  • 8
    A spring block system in horizontal oscillation has a time-period $T$. Now the spring is cut into four equal parts and the block is re-connected with one of the parts. The new time period of vertical oscillation will be
    View Solution
  • 9
    A system exhibiting S.H.M. must possess
    View Solution
  • 10
    A particle of mass $10\, gm$ moves in a field where potential energy per unit mas is given by expression $v = 8 \times 10^4\, x^2\, erg/gm$. If the total energy of the particle is $8 \times 10^7\, erg$ then the relation between $x$ and time $t$ is
    View Solution