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Electrostatics — Physics STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 SciencePhysicsElectrostatics2 Marks
Question
Two parallel plates have a potential difference of $10\ V$ between them. If the plates are $0.5\ mm$ apart, what will be the strength of electric charge.
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Answer

$ V=10 V$
$d=0.5 mm =0.5 \times 10^{-3} m $
To find: The strength of electric field $(E)$
Formula: $E =\frac{V}{d}$
Calculation: From formula,
$ E=\frac{10}{0.5 \times 10^{-3}}$
$20 \times 10^3 V / m $

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