MCQ
Two pi and half sigma bonds are present in
- A$O_2^ + $
- B$N_2$
- C$O_2$
- ✓$N_2^ + $
${N_2} \Rightarrow B.O. = 3.0 \Rightarrow [\pi - Bond = 2\,\& \sigma - Bond = 1]$
${O_{{2^ \oplus }}} = B.O. \Rightarrow 2.5 \Rightarrow [\pi - Bond = 1.5\,\& \sigma - Bond = 1]$
${O_2} \Rightarrow B.O. \Rightarrow 2 \Rightarrow [\pi - Bond \Rightarrow 1\,\& \sigma - Bond = 1]$
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$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.
$(b)$ Each boron atom is in sp $^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement(s) is :
$(ii)\, F_{(g)} + e^- \to F^-_{(g)}, \Delta H_2$
$(iii)\, Cl_{(g)} + e^- \to Cl_{(g)}, \Delta H_3$
$(iv)\, O_{(g)}^- + e^- \to O_{(g)}^{2-} , \Delta H_4$
That according to given information the incorrect statement is